(2xy+y)dx+(x^2-x)dy=0

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Solution for (2xy+y)dx+(x^2-x)dy=0 equation:


Simplifying
(2xy + y) * dx + (x2 + -1x) * dy = 0

Reorder the terms for easier multiplication:
dx(2xy + y) + (x2 + -1x) * dy = 0
(2xy * dx + y * dx) + (x2 + -1x) * dy = 0

Reorder the terms:
(dxy + 2dx2y) + (x2 + -1x) * dy = 0
(dxy + 2dx2y) + (x2 + -1x) * dy = 0

Reorder the terms:
dxy + 2dx2y + (-1x + x2) * dy = 0

Reorder the terms for easier multiplication:
dxy + 2dx2y + dy(-1x + x2) = 0
dxy + 2dx2y + (-1x * dy + x2 * dy) = 0
dxy + 2dx2y + (-1dxy + dx2y) = 0

Reorder the terms:
dxy + -1dxy + 2dx2y + dx2y = 0

Combine like terms: dxy + -1dxy = 0
0 + 2dx2y + dx2y = 0
2dx2y + dx2y = 0

Combine like terms: 2dx2y + dx2y = 3dx2y
3dx2y = 0

Solving
3dx2y = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '3'.
dx2y = 0

Simplifying
dx2y = 0

The solution to this equation could not be determined.

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